4=1.5x^2+2x+10

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Solution for 4=1.5x^2+2x+10 equation: 



4=1.5x^2+2x+10

We move all terms to the left:

4-(1.5x^2+2x+10)=0

We get rid of parentheses

-1.5x^2-2x-10+4=0

We add all the numbers together, and all the variables

-1.5x^2-2x-6=0

a = -1.5; b = -2; c = -6;
Δ = b2-4ac
Δ = -22-4·(-1.5)·(-6)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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